Primitives for Ambiguous Non-Deterministic Computation
AMB is the ambiguous special form for non-deterministic computation.
usage
(import :std/amb)
Special Forms
begin-amb
(begin-amb body ...)
Evaluates body in a fresh amb scope; you should always wrap the beginning of ambiguous computation
in a begin-amb
form to avoid side-effects leaking between amb executions.
begin-amb-random
(begin-amb-random body ...)
Like begin-amb
, but the search strategy for generating amb values is randomized.
amb
(amb expr ...)
The ambiguous operator; may evaluate and return the value of any expression operand.
The order with which the values are generated depends on the search strategy.
After v0.16-56-g6fb422de
by default it is deterministic, unless the computation is within
a begin-amb-random
scope, in which case it is randomized.
Prior to v0.16-56-g6fb422de
the search strategy was always randomized.
amb-find
(amb-find expr [failure]) -> any
Evaluates expr
returning its value if successful, possibly after backtracking.
If the expression tree is exhausted, then failure
is evaluated for the result;
if failure
is not specified, then an error is raised.
one-of
(one-of expr)
Same as (amb-find expr)
amb-collect
(amb-collect expr) -> list
Evaluates expr
and performs backtracking repeatedly, collecting all possible
values in a list.
all-of
(all-of expr) -> list
Same as (amb-collect expr)
.
amb-assert
(amb-assert expr)
Evaluates expr
, failing if it is #f
.
required
(required expr)
Same as (amb-assert expr)
amb-do
(amb-do thunks) -> any
thunks := list of thunk
Procedural form of amb
amb-do-find
(amb-do-find thunk [failure]) -> any
thunk, failure := thunk
Procedural form of amb-find
amb-do-collect
(amb-do-collect thunk) -> list
Procedural form of amb-collect
amb-exhausted?
(amb-exhausted? e) -> boolean
Predicate that returns true if e is an exception raised because the amb search was exhausted.
element-of
(element-of list) -> any
Ambiguous choice from a list; may evaluate and return any element of list.
Example
Here is the well known dwelling house puzzle:
(def (solve-dwelling-puzzle)
(begin-amb
(let ((baker (amb 1 2 3 4 5))
(cooper (amb 1 2 3 4 5))
(fletcher (amb 1 2 3 4 5))
(miller (amb 1 2 3 4 5))
(smith (amb 1 2 3 4 5)))
;; They live on different floors.
(required (distinct? (list baker cooper fletcher miller smith)))
;; Baker does not live on the top floor.
(required (not (= baker 5)))
;; Cooper does not live on the bottom floor.
(required (not (= cooper 1)))
;; Fletcher does not live on either the top or the bottom floor.
(required (not (= fletcher 5)))
(required (not (= fletcher 1)))
;; Miller lives on a higher floor than does Cooper.
(required (> miller cooper))
;; Smith does not live on a floor adjacent to Fletcher's.
(required (not (= (abs (- smith fletcher)) 1)))
;; Fletcher does not live on a floor adjacent to Cooper's.
(required (not (= (abs (- fletcher cooper)) 1)))
`((baker ,baker) (cooper ,cooper) (fletcher ,fletcher) (miller ,miller) (smith ,smith)))))
(def (distinct? lst)
(let lp ((rest lst))
(match rest
([hd . rest]
(and (not (memq hd rest))
(lp rest)))
(else #t))))
(solve-dwelling-puzzle) ;=> '((baker 3) (cooper 2) (fletcher 4) (miller 5) (smith 1))